Op-Amp Experimentation 1: Op-Amp Basics

Op-Amp Experimentation 2: Basic Circuit Math

Op-Amp Experimentation 3: Op-Amp Applications

Op-Amp Experimentation 4: From Ideal to Real

Op-Amp Experimentation 5: Integrator

Op-Amp Experimentation 6: Differentiator

Op Amp Experimentation 7: PID Controller – coming soon
Okay, so I’m not going to post the math proving the equations, just some fun examples of what you can do with op-amps.


The equation is {V_{out}} =  - {R_f}\left( {{{{V_1}} \over {{R_1}}} + {{{V_2}} \over {{R_2}}} + ... + {{{V_n}} \over {{R_n}}}} \right)     and if the resistors are all equal, then it is {V_{out}} =  - \left( {{V_1} + {V_2} + ... + {V_n}} \right).


Op Amp Multiplication
Here we have a multiplication circuit. This is actually pretty interesting, because the first two op amps take the natural log of the two inputs, then the second op amp adds them and solves the exponential of the sum. This is based on the fact that log(a*b)=log a + log b. I won’t bother posting the equation to this, because there is a much simpler way of doing things that doesn’t result in a 0.6V drop from the diodes.

The equation for this is {V_{out}} = {{{R_2}} \over {{R_1}}}{{{v_1}{v_2}} \over {{V_{ref}}}}


This is interesting, I haven’t found any quick examples on this. However I think the easiest way would be to use a relationship similar to the one used for multiplication, although use the identity log(x/y) = log(x) – log(y). If anyone figures this out let me know, I’d love to include a picture.


Turns out it is pretty easy to do calculus with op-amps, as long as you understand that capacitors and inductors vary voltage/current with the rate of change of voltage/current. Here is a way to do integration

The equation for this as long as {R_n} = {1 \over {{1 \over {{R_i}}} + {1 \over {{R_f}}}}}  is

{V_{out}}\left( {{t_1}} \right) = {V_{out}}({t_0}) - {1 \over {{R_i}{C_f}}}\int\limits_{{t_0}}^{{t_1}} {{V_{in}}\left( t \right)dt}


An easy way to differentiate a signal is to use the circuit below:

The equation: {V_{out}} =  - RC{{d{V_{in}}} \over {dt}}


We already saw an example of this in the multiplication circuit, but here it is:

The equation is {V_{out}} = {V_T}\ln \left( {{{{V_{in}}} \over {{I_S}R}}} \right)

Where {{I_S}} is the saturation current and {V_T} is the thermal voltage of the diode.


Similar to the logarithmic setup, the exponential setup is

And the equation is {V_{out}} =  - R{I_S}{e^{{{{V_{in}}} \over {V & t}}}}

Sine Wave

Last one! To create an accurate sine wave we can use a  Wien Bridge to generate an accurate sine wave.

The equation: f = {1 \over {2\pi RC}} . The component at the top is a light bulb – this is used so that it will heat up until its resistance {R_b} = {R \over 2}. Now the resistors and capacitors do not need to equal each other, but it makes the math much simpler. I am not very familiar with these, so I’ll be sure to test it out later on.

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